Alright so the "reptile" section has been no help to me, but I figure that someone can answer this even if they're not familiar with herpetoculture so long as they get math. I don't. I breed western hognoses (Tiny, harmless, pigsnouted snakes from Texas. Like to eat frogs and play dead when they're frightened) and am hoping to get into some higher end morphs ("fancy colors/patterns") this summer. My endgame would be the snow superconda, a patternless white animal, and I want you guys to help me figure out what happens if I were to breed two anaconda het snows together. There's three morphs involved, so I'll break it down.
ANACONDA GENE - This is a codominant or incomplete dominant morph that affects pattern. An anaconda is a reduced patterned animal. Breed it to a normal and get half normals and half anacondas. Breed two anacondas and get half anacondas, a quarter normals, and a quarter supercondas. Supercondas have no pattern at all. Breed a superconda to a normal and get all anacondas. Breed a superconda to an anaconda and get half of each.
AMELANISM GENE - this is a simple recessive morph that affects color, they produce all pigments except for melanin. You breed an "albino" to a normal and get offspring that are "het for albino" or look normal, but carry the hidden gene. You breed a normal to a het and you get half hets and half normals. You breed two hets together and you get a quarter albinos, a quarter normals, and a half hets. You breed a het to a visual albino and get half hets and half visuals. You breed two visuals and get a full clutch of visuals.
ANERYTHERISTIC GENE - (I honestly believe it's axanthic in hogs, but lets call it anery anyways.) This is another simple recessive gene that affects color, acts the same as the previous, but visually is almost the opposite of albino where now the only pigment they have is melanin. If you mix anerys to albinos then they cross each other out and produce a white animal with no pigment called a "snow". To get a snow, you breed an albino to an anery to produce hets and then breed those hets together to get 1/16 normals, 2/16 het albino, 2/16 het anery, 4/16 double hets, 1/16 plain albino, 1/16 plain anery, 2/16 anery het albino, 2/16 albino het anery, and 1/16 chance of a visual snow!
It's simple punnet squares, I just don't know how to add the co-dom anaconda gene into this all. So if you guys survived that wall of text and want to take a crack at it I WANT TO KNOW WHAT I SHOULD GET AND WHAT ARE THEIR ODDS IF I BREED TWO ANACONDA HET SNOWS TOGETHER! Anaconda = co-dom and Snow = two simple recessive genes. I'm thinking that now we're in the 1/64 or 1/28 chance of hitting a visual snow superconda, which is horrible odds, but still I'd get anery condas and such. Also good...
THANK YOU ALL SO MUCH IN ADVANCE!
ANACONDA GENE - This is a codominant or incomplete dominant morph that affects pattern. An anaconda is a reduced patterned animal. Breed it to a normal and get half normals and half anacondas. Breed two anacondas and get half anacondas, a quarter normals, and a quarter supercondas. Supercondas have no pattern at all. Breed a superconda to a normal and get all anacondas. Breed a superconda to an anaconda and get half of each.
AMELANISM GENE - this is a simple recessive morph that affects color, they produce all pigments except for melanin. You breed an "albino" to a normal and get offspring that are "het for albino" or look normal, but carry the hidden gene. You breed a normal to a het and you get half hets and half normals. You breed two hets together and you get a quarter albinos, a quarter normals, and a half hets. You breed a het to a visual albino and get half hets and half visuals. You breed two visuals and get a full clutch of visuals.
ANERYTHERISTIC GENE - (I honestly believe it's axanthic in hogs, but lets call it anery anyways.) This is another simple recessive gene that affects color, acts the same as the previous, but visually is almost the opposite of albino where now the only pigment they have is melanin. If you mix anerys to albinos then they cross each other out and produce a white animal with no pigment called a "snow". To get a snow, you breed an albino to an anery to produce hets and then breed those hets together to get 1/16 normals, 2/16 het albino, 2/16 het anery, 4/16 double hets, 1/16 plain albino, 1/16 plain anery, 2/16 anery het albino, 2/16 albino het anery, and 1/16 chance of a visual snow!
It's simple punnet squares, I just don't know how to add the co-dom anaconda gene into this all. So if you guys survived that wall of text and want to take a crack at it I WANT TO KNOW WHAT I SHOULD GET AND WHAT ARE THEIR ODDS IF I BREED TWO ANACONDA HET SNOWS TOGETHER! Anaconda = co-dom and Snow = two simple recessive genes. I'm thinking that now we're in the 1/64 or 1/28 chance of hitting a visual snow superconda, which is horrible odds, but still I'd get anery condas and such. Also good...
THANK YOU ALL SO MUCH IN ADVANCE!
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Okay, let's see if I understand this. I'm going to use X x for dominant/recessive albino trait, and Y y for dominant/recessive anery trait. You breed an xxYY animal with an XXyy animal to get offspring that are XxYy, and then cross these. I'm not completely sure what you mean when you say a "het snow", but I'm guessing it's those XxYy animals.
Now, the anaconda trait is Zz. ZZ is normal, Zz is anaconda, zz is superconda - at least that's what I'm getting from your descr
Now, the anaconda trait is Zz. ZZ is normal, Zz is anaconda, zz is superconda - at least that's what I'm getting from your descr
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keywords: and,involving,snake,long,genetics,punnet,math,squares,Unique,text,10,POINTS,question,10 POINTS - Unique math question involving snake genetics and punnet squares. (long text)