What is the mechanism between 2 chloro methylpentane and sodium methoxide
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What is the mechanism between 2 chloro methylpentane and sodium methoxide

[From: ] [author: ] [Date: 12-06-15] [Hit: ]
The carbon upon which the chlorine is bonded is a tertiary carbon, therefore, formation of a localized carbocation is relatively stable.It would then be attacked by the electrons on the oxygen of the methoxide.......
I feel like it should be E2 to best describe it, but is there a possibility of it being SN1? I saw a question where ethoxide was used instead of methoxide, and the result was E2.

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so it's what compound again? 2-chloro--methylpentane? you need to specify the location of the methyl substituent

EDIT:
I'll assume you meant 2-chloro-2-methylpentane...in which case, since Cl is an excellent leaving group, if there is a substitution, it would proceed by Sn1. The carbon upon which the chlorine is bonded is a tertiary carbon, therefore, formation of a localized carbocation is relatively stable. It would then be attacked by the electrons on the oxygen of the methoxide.
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