You are driving down the highway late one night at 20 m/s when a deer steps onto the road 35 m in front of you. Your reaction time before stepping on the brakes is 0.50 s, and the maximum deceleration of your car is 10 m/s^2 .
How much distance is between you and the deer when you come to a stop? (Answer in meters)
Can anyone at least explain how to set up this problem?
Thank you very much in advance!!
How much distance is between you and the deer when you come to a stop? (Answer in meters)
Can anyone at least explain how to set up this problem?
Thank you very much in advance!!
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distance traveled in 0.50 s = 20 X 0.50 = 10 m
Now, distance traveled during deceleration = 20^2/(2 X 10) = 20 m
(v^2 = u^2-2as; here, v = 0, u = 20 m/s, a = 10 m/s^2)
(checkout: http://en.wikipedia.org/wiki/Acceleratio…
So, total distance traveled = 10 + 20 = 30 m
Ans:35-30 = 5 m
Similar Problem:
distance traveled in 0.50 s = 20 X 0.50 = 10 m
distance traveled during deceleration = 20^2/(2 X 6.0) = 33.33 m
total distance traveled = 43.33 m
So, collision can be avoided.
Now, distance traveled during deceleration = 20^2/(2 X 10) = 20 m
(v^2 = u^2-2as; here, v = 0, u = 20 m/s, a = 10 m/s^2)
(checkout: http://en.wikipedia.org/wiki/Acceleratio…
So, total distance traveled = 10 + 20 = 30 m
Ans:35-30 = 5 m
Similar Problem:
distance traveled in 0.50 s = 20 X 0.50 = 10 m
distance traveled during deceleration = 20^2/(2 X 6.0) = 33.33 m
total distance traveled = 43.33 m
So, collision can be avoided.