Was wondering if anyone could help me out here.
How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102
And just to let you know the number twos to the right of x's and brackets represent squared.
I've been looking at it for ages and just cannot understand it This if for GCSE Maths btw
The * represent times
thanks for your help
How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102
And just to let you know the number twos to the right of x's and brackets represent squared.
I've been looking at it for ages and just cannot understand it This if for GCSE Maths btw
The * represent times
thanks for your help
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(1/3) * pi * x^2 * 3 + (1/3) * pi * (x+1)^2 * 6 = 102 * pi. There is a factor pi in each
term of the equation so it can be cancelled. In the first term there the (1/3) and 3
multiply together to get 1, and in the second term the (1/3) and 6 multiply together
to get 2. Thus the equation becomes x^2 + 2*(x+1)^2 = 102. Now expand this to
get x^2 + 2*(x^2 + 2x + 1) = 102 ---> x^2 + 2*x^2 + 4x + 2 = 102 which can then
be further simplified to 3*x^2 + 4x = 100 or x*(3x + 4) = 100.
term of the equation so it can be cancelled. In the first term there the (1/3) and 3
multiply together to get 1, and in the second term the (1/3) and 6 multiply together
to get 2. Thus the equation becomes x^2 + 2*(x+1)^2 = 102. Now expand this to
get x^2 + 2*(x^2 + 2x + 1) = 102 ---> x^2 + 2*x^2 + 4x + 2 = 102 which can then
be further simplified to 3*x^2 + 4x = 100 or x*(3x + 4) = 100.