How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102
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How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102

[From: ] [author: ] [Date: 12-06-11] [Hit: ]
thanks for your help-(1/3) * pi * x^2 * 3 + (1/3) * pi * (x+1)^2 * 6 = 102 * pi.term of the equation so it can be cancelled.multiply together to get 1,to get 2. Thus the equation becomes x^2 + 2*(x+1)^2 = 102.be further simplified to 3*x^2 + 4x = 100 or x*(3x + 4) = 100.......
Was wondering if anyone could help me out here.

How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102

And just to let you know the number twos to the right of x's and brackets represent squared.

I've been looking at it for ages and just cannot understand it This if for GCSE Maths btw

The * represent times

thanks for your help

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(1/3) * pi * x^2 * 3 + (1/3) * pi * (x+1)^2 * 6 = 102 * pi. There is a factor pi in each

term of the equation so it can be cancelled. In the first term there the (1/3) and 3

multiply together to get 1, and in the second term the (1/3) and 6 multiply together

to get 2. Thus the equation becomes x^2 + 2*(x+1)^2 = 102. Now expand this to

get x^2 + 2*(x^2 + 2x + 1) = 102 ---> x^2 + 2*x^2 + 4x + 2 = 102 which can then

be further simplified to 3*x^2 + 4x = 100 or x*(3x + 4) = 100.
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keywords: Pi,become,How,102,does,How does 1/3 * Π*x 2 *3 + 1/3* Π*(x+1) 2 *6 = 102Π become x2 + 2x 2 + 4x +2 =102
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