It is a displacement vs time graph. It is described as followed; 0 - 10 s is 0 - 10m. 10 - 20s is 10 - 20m. 20 - 30 s is 20m. From 30 - 40 s is 20m - 15m. From 40s to 50s is 15 - 10m. (The speed is uniform increasing by 1m per 1s. I wrote 15m / 40s and it was marked incorrectly.
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The velocity is the slope of the displacement vs time graph
When the velocity is constant, the velocity is the instantaneous velocity.
v = displacement ÷ time
Displacement = final position – initial position
It is a displacement vs time graph. It is described as followed;
0 - 10 s is 0 - 10m, d = 10 – 0 = 10, v = 10 ÷ 10 = 1 m/s
The velocity is constant, so the instantaneous velocity = 1 m/s
10 - 20s is 10 - 20m, d = 20 – 10 = 10, v = 10 ÷ 10 = 1 m/s
The velocity is constant, so the instantaneous velocity = 1 m/s
For the first 20 seconds, the slope of the graph is +1. So the instantaneous velocity is +1 m/s for the first 20 seconds.
20 - 30 s is 20m, d = 20 – 20 = 0, v = 0÷ 10 = 0 m/s
The velocity is constant, so the instantaneous velocity = 0 m/s
From t = 20 to t = 30, the slope of graph = 0, so the instantaneous velocity = 0 m/s
30 - 40 s is 20m - 15m, d = 15 – 20 = 0-5, v = -5 ÷ 10 = -0.5 m/s
The velocity is constant, so the instantaneous velocity = -0.5 m/s
From t = 30 to t = 40, the slope of graph = -0.5, so the instantaneous velocity = -0.5 m/s
40s to 50s is 15 - 10m, d = 10 – 15 = -5, v = -5 ÷ 10 = -0.5 m/s
From t = 40 to t = 50, the slope of graph = -0.5, so the instantaneous velocity = -0.5 m/s
The slope of your displacement vs time graph at a specific point is the instantaneous velocity at that point!
In this problem, the instantaneous velocity = +1 m/s for the first 20 seconds
0 m/s for the next 10 seconds, and -0.5 m/s for the last 20 seconds!
When the velocity is constant, the velocity is the instantaneous velocity.
v = displacement ÷ time
Displacement = final position – initial position
It is a displacement vs time graph. It is described as followed;
0 - 10 s is 0 - 10m, d = 10 – 0 = 10, v = 10 ÷ 10 = 1 m/s
The velocity is constant, so the instantaneous velocity = 1 m/s
10 - 20s is 10 - 20m, d = 20 – 10 = 10, v = 10 ÷ 10 = 1 m/s
The velocity is constant, so the instantaneous velocity = 1 m/s
For the first 20 seconds, the slope of the graph is +1. So the instantaneous velocity is +1 m/s for the first 20 seconds.
20 - 30 s is 20m, d = 20 – 20 = 0, v = 0÷ 10 = 0 m/s
The velocity is constant, so the instantaneous velocity = 0 m/s
From t = 20 to t = 30, the slope of graph = 0, so the instantaneous velocity = 0 m/s
30 - 40 s is 20m - 15m, d = 15 – 20 = 0-5, v = -5 ÷ 10 = -0.5 m/s
The velocity is constant, so the instantaneous velocity = -0.5 m/s
From t = 30 to t = 40, the slope of graph = -0.5, so the instantaneous velocity = -0.5 m/s
40s to 50s is 15 - 10m, d = 10 – 15 = -5, v = -5 ÷ 10 = -0.5 m/s
From t = 40 to t = 50, the slope of graph = -0.5, so the instantaneous velocity = -0.5 m/s
The slope of your displacement vs time graph at a specific point is the instantaneous velocity at that point!
In this problem, the instantaneous velocity = +1 m/s for the first 20 seconds
0 m/s for the next 10 seconds, and -0.5 m/s for the last 20 seconds!