Alright so...
y= -(x+2)^2.
Could someone tell me whether or not I got these wrong?
For the vertex: (-2,0)
Axis of Symmetry or line of symmetry: x=-2
Maximum: y=0
y-intercept= y= (0,-4)
and for the x-intercept, I know I got this wrong, so I'll need someone to help me out. S'il vous plait, merci.
y= -(x+2)^2
0= -(x+2)^2
0= -(x^2+4x+4)
0= -x^2 -4x -4
and I have no clue.
y= -(x+2)^2.
Could someone tell me whether or not I got these wrong?
For the vertex: (-2,0)
Axis of Symmetry or line of symmetry: x=-2
Maximum: y=0
y-intercept= y= (0,-4)
and for the x-intercept, I know I got this wrong, so I'll need someone to help me out. S'il vous plait, merci.
y= -(x+2)^2
0= -(x+2)^2
0= -(x^2+4x+4)
0= -x^2 -4x -4
and I have no clue.
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the x-intercept in this case is the same as the vertex (-2,0)
If you have a polynomial in the form ax^2 + bx+c = 0, you factor it and the "solutions" are your x-intercepts.
In this case, you already have it factored -(x+2)^2, so you know that the x-intercept is -2 just by looking at it.
If you have a polynomial in the form ax^2 + bx+c = 0, you factor it and the "solutions" are your x-intercepts.
In this case, you already have it factored -(x+2)^2, so you know that the x-intercept is -2 just by looking at it.
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Your calculations seem to be impeckable but the french should be : Silvia go splatt? Mercy!
But that may be the cajun translation and not real Canadian French and certainly not Froggie type.
But that may be the cajun translation and not real Canadian French and certainly not Froggie type.
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well if the vertex is (-2,0) then there will be no x intercepts