76) Find the exact value of the expression arctan(tan(5pi/4))
75) Find the exact value of the expression arcsin(sin(-5pi/5))
74) Find the exact value of the expression arccos(cos(-3pi/8))
79) a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
(tan x)^2 + tan x − 30 = 0 on (−π/2, π/2)
x= ?
b) Use a calculator to approximate the solution in part (a) to three decimal places. (Enter your answers as a comma-separated list.)
x= ?
75) Find the exact value of the expression arcsin(sin(-5pi/5))
74) Find the exact value of the expression arccos(cos(-3pi/8))
79) a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
(tan x)^2 + tan x − 30 = 0 on (−π/2, π/2)
x= ?
b) Use a calculator to approximate the solution in part (a) to three decimal places. (Enter your answers as a comma-separated list.)
x= ?
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76) Find the exact value of the expression arctan(tan(5pi/4))
tan(5pi/4) = 1
arctan(tan(5pi/4)) = arctan(1) = π/4
tanθ => -π/2 ≤ θ ≤ π/2
75) Find the exact value of the expression arcsin(sin(-5pi/4))
sin(-5pi/5) = sin(- π) = 0
arcsin(sin(-5pi/5)) = arcsin(0) = 0
74) Find the exact value of the expression arccos(cos(-3pi/8))
cos(-θ) = cosθ
arccos(cos(-3pi/8)) = 3π/8
79) a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
(tan x)^2 + tan x − 30 = 0 on (−π/2, π/2)
(tanx+6)(tanx-5)=0
tanx=-6
tanx=5
x = arctan-6, arctan 5
tan(5pi/4) = 1
arctan(tan(5pi/4)) = arctan(1) = π/4
tanθ => -π/2 ≤ θ ≤ π/2
75) Find the exact value of the expression arcsin(sin(-5pi/4))
sin(-5pi/5) = sin(- π) = 0
arcsin(sin(-5pi/5)) = arcsin(0) = 0
74) Find the exact value of the expression arccos(cos(-3pi/8))
cos(-θ) = cosθ
arccos(cos(-3pi/8)) = 3π/8
79) a) Solve the equation on the given interval, expressing the solution for x in terms of inverse trigonometric functions. (Enter your answers as a comma-separated list.)
(tan x)^2 + tan x − 30 = 0 on (−π/2, π/2)
(tanx+6)(tanx-5)=0
tanx=-6
tanx=5
x = arctan-6, arctan 5