integrate
√ tan^5 x (sec^2 x)
for clarity, the question is about
the square root of 5 times of tanx times the 2 times of secx
I hope you know what I MEAN!
tks~
√ tan^5 x (sec^2 x)
for clarity, the question is about
the square root of 5 times of tanx times the 2 times of secx
I hope you know what I MEAN!
tks~
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The "for clarity" bit didn't really help, in particular you didn't clarify whether the square root should also encompass the sec^2 x, but I'll assume it doesn't as that's far more likely.
∫ (tan x)^(5/2) sec^2 x dx: let u = tan x, du = sec^2 x dx
= ∫u^(5/2) du
= (2/7) u^(7/2) + c
= (2/7) √(tan^7 x) + c.
∫ (tan x)^(5/2) sec^2 x dx: let u = tan x, du = sec^2 x dx
= ∫u^(5/2) du
= (2/7) u^(7/2) + c
= (2/7) √(tan^7 x) + c.
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This is an easy question. Don't you know your basic Trig functions? There are a few integral laws you should remember. Also is this indefinite integration?
And the guy above me is right. Do your own homework. This will not take you more than 5 mins. Good luck
And the guy above me is right. Do your own homework. This will not take you more than 5 mins. Good luck
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Do your own Homework
Good luck
Good luck