Chemistry question???
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Chemistry question???

[From: ] [author: ] [Date: 12-02-29] [Hit: ]
06^2*0.03)=0.......
balance: SO2(g)+O2(g)------->SO3(g)
the concentration of SO2 and O2 are determined to be [0.06] and [0.03] if the following reaction has a Kc of 3.6x10^2, what is the concentration of SO3????

any work would be much appreciated thank you!!

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Balanced Equation:
2SO2 + O2 -----> 2SO3

Kc = [SO3]^2 / {[SO2]^2 [O2]}

360 = [SO3]^2 / ((0.06)^2 (0.03))
[SO3]^2 = 360 (0.06)^2 (0.03) = 0.03888
[SO3] = (0.03888)^0.5 = 0.197

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balanced: 2 SO2(g) + O2(g)-------> 2 SO3(g)

Kc=[SO3]^2/([SO2(g)]^2*[O2]) therefore [SO3]=sqrt( [SO2(g)]^2*[O2]*Kc) = sqrt(3.6x10^2*0.06^2*0.03)=0.197

I think
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