They have agreed that each will arrive at a random time between 11:00A.M and 12:00 noon and that each will wait for the other for 8 minutes or until 12:00 noon. Otherwise, the first to arrive will leave. Find the probability the two will actually have lunch together this Saturday. Express your answer as a common fraction reduced to lowest terms.
Please explain.
Thanks!
Please explain.
Thanks!
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this is solved easily using geometry.
imagine a 60 x 60 (minutes) square on a graph. it represents all possibilities of the 2 friends arriving.
a main diagonal is from (0,0) to (60,60)
draw 2 lines parallel to the diagonal, one 8 minutes above the diagonal, and one 8 minutes below the diagonal.
the 2 triangles outside these 2 lines represent the friends NOT meeting
a look at a diagram for a similar problem will help to understand
http://mindyourdecisions.com/blog/2011/0…
P(they meet) = 1 - 52*52/(60*60) = 56/225 <-------
imagine a 60 x 60 (minutes) square on a graph. it represents all possibilities of the 2 friends arriving.
a main diagonal is from (0,0) to (60,60)
draw 2 lines parallel to the diagonal, one 8 minutes above the diagonal, and one 8 minutes below the diagonal.
the 2 triangles outside these 2 lines represent the friends NOT meeting
a look at a diagram for a similar problem will help to understand
http://mindyourdecisions.com/blog/2011/0…
P(they meet) = 1 - 52*52/(60*60) = 56/225 <-------
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This is a ridiculous way to meet people.