Probability Problem! Two friends have agreed to meet for lunch this Saturday...
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Probability Problem! Two friends have agreed to meet for lunch this Saturday...

[From: ] [author: ] [Date: 12-02-21] [Hit: ]
Please explain.Thanks!-this is solved easily using geometry.imagine a 60 x 60 (minutes) square on a graph. it represents all possibilities of the 2 friends arriving.a main diagonal is from (0,......
They have agreed that each will arrive at a random time between 11:00A.M and 12:00 noon and that each will wait for the other for 8 minutes or until 12:00 noon. Otherwise, the first to arrive will leave. Find the probability the two will actually have lunch together this Saturday. Express your answer as a common fraction reduced to lowest terms.


Please explain.


Thanks!

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this is solved easily using geometry.
imagine a 60 x 60 (minutes) square on a graph. it represents all possibilities of the 2 friends arriving.
a main diagonal is from (0,0) to (60,60)
draw 2 lines parallel to the diagonal, one 8 minutes above the diagonal, and one 8 minutes below the diagonal.
the 2 triangles outside these 2 lines represent the friends NOT meeting
a look at a diagram for a similar problem will help to understand
http://mindyourdecisions.com/blog/2011/0…
P(they meet) = 1 - 52*52/(60*60) = 56/225 <-------

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This is a ridiculous way to meet people.
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