Trig question, please help (C2)

Find all values of x between 0 < x < 360 satisfying..?

5cos² + 2 = 3sin²x - 2cosx

Thanks:)

5cos^2x + 2 = 3sin^2x - 2cosx
5cos^2x + 2 = 3(1 - cos^2x) - 2cosx
5cos^2x + 2 = 3 - 3cos^2x - 2cosx
8cos^2x + 2cosx - 1 = 0
(4cosx - 1)(2cosx + 1) = 0
4cosx - 1 = 0 or 2cosx + 1 = 0
cosx = 1/4 or cosx = -1/2
x = 75.5 or x = 105.5 or x = 120 or x = 240

Re-state the problem.