Help with algebra 1 problem

Write a linear equation.

A shipment of tv sets, some weighing 30kg each and the others weighing 50 kh each, has a total weight of 880kg. If there are 20 TV sets all together, how many weigh 50kg.

I just need the 2 equations. But it would be
great if you help me solve it.
Thanks. :)

Say TVs weighing 30kg are x in number and those weighing 50Kg are y in number.
Based on their total weight we can write first equation
30x + 50y = 880
Based on the quantity we can write the second equation
x + y = 20
From the second equation we can say
x = 20 - y
Put this in first equation
30(20 - y) + 50y = 880

or
600 - 30y + 50y = 880

or
20y = 880 - 600

or
20y = 280

or y = 280 / 20

or y = 14

So total TVs weighing 50 kg are 14

Let X = the # of 30kg TVs, and let Y = the # of 50kg TVS.

Then your 2 equations will be:

X + Y = 20 (since there are 20 TVs total)
30X + 50Y = 880 (since the total weight of the TVs is 880 kg)

You can then solve using the elimination method (multiply the top equation by -30 and then add the 2 equations...the X variable will cancel out and you get 20Y = 280, so Y = 14).

Hope this helps. Cheers!

Let x = the # of 30kg TV's
20-x = the # of 50kg TV's

30(x) + 50(20-x) = 880

30x + 1000 - 50x = 880

-20 x = -120

x = 6

Thus the # of 30 kg TV's is 6 and the # of 50kg TV's is 14.

let total no of tv sets that weigh 30 be x
so
30x+(20-x)*50=880
solve for x.
the ans is 20 - x
the final ans should be 14 tv sets weigh 50kg

30x + 50y = 880
x + y = 20


x = 20 - y

30(20-y) + 50y = 880

600 - 30y + 50 y = 880

600 + 20y = 880

20y = 280
y = 14

x = 20 - 14 = 6

6 weighing 30kg
and 14 weighing 50 kg

Jen

just eq?
so:
let tv sets be x,y:
30x+50y=880

x+y=50
glad to help

x+y=20
30x+50y=880