log (base 3) 81= 4/3 log (base 2) 8
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log[3](81) = (4/3) * log[2](8)
log[3](3^4) = (4/3) * log[2](2^3)
4 * log[3](3) = (4/3) * 3 * log[2](2)
4 * 1 = 4 * 1
4 = 4
log[3](3^4) = (4/3) * log[2](2^3)
4 * log[3](3) = (4/3) * 3 * log[2](2)
4 * 1 = 4 * 1
4 = 4
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Recall that if log(base a) b = c, then it follows that a^c = b.
log(base 3) 81 = 4
4/3*log(base 2) 8 = 4/3 * 3 = 4
So both sides are equal.
log(base 3) 81 = 4
4/3*log(base 2) 8 = 4/3 * 3 = 4
So both sides are equal.
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it is true because both equal 4.