If cos x = sqrt(3)/2 and -pi/2 <= x <= 0, what the the exact value of x in radians?
i got 1/6pi (30 deg) but why is the answer -1/6pi? is it because the interval goes from -90deg to 0? if it was from 0 to -90deg would it then be positive??
i got 1/6pi (30 deg) but why is the answer -1/6pi? is it because the interval goes from -90deg to 0? if it was from 0 to -90deg would it then be positive??
-
Correct. The answer is -1/6pi because the interval is negative. If the interval was from 0 to pi/2, then your answer would be correct.
-
x = -pi/6 + 2kpi => forgot this one
x = pi/6 + 2kpi
x = pi/6 + 2kpi