Help with this problem, please!!!!
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okay for sin^5/2x you can split that up into sin^1/2x*sin^2x
sin^1/2xcosx-sin^1/2x*sin^2xcosx
now you can factor out a sin^1/2xcosx
sin^1/2xcosx(1-sin^2x)
remember identites: sin^2x+cos^2x=1 so 1-sin^2x=cos^2x
sin^1/2xcosx(cos^2x)
now multiply everything out
sin^1/2xcos^3x.
YOu'll find out that factoring when you are trying to verify an identity becomes very helpful because it helps simplifies the problem down to something that you can recognize.
sin^1/2xcosx-sin^1/2x*sin^2xcosx
now you can factor out a sin^1/2xcosx
sin^1/2xcosx(1-sin^2x)
remember identites: sin^2x+cos^2x=1 so 1-sin^2x=cos^2x
sin^1/2xcosx(cos^2x)
now multiply everything out
sin^1/2xcos^3x.
YOu'll find out that factoring when you are trying to verify an identity becomes very helpful because it helps simplifies the problem down to something that you can recognize.
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sin^1/2x cosx - sin^5/2x cosx
= sin^1/2x cosx (1-sin^2x)
= sin^1/2x cosx cos^2x
= cos^3x √sinx
= sin^1/2x cosx (1-sin^2x)
= sin^1/2x cosx cos^2x
= cos^3x √sinx