The problem is
log 50-log 16-log 50
and the base is four. I know that the answer is -2, but I am not quite sure how to get there :/ any help would be appreciated! thanks!
log 50-log 16-log 50
and the base is four. I know that the answer is -2, but I am not quite sure how to get there :/ any help would be appreciated! thanks!
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Subracting logs is the same as dividing what is inside the log, so log50 - log16 = log(50/16).
log(50/16) - log50 = log(50/16*50) (16*50 because both are in the denominator)
50/16*50 is the same as 1/16
Log base 4 of 1/16. What exponent would you use on 4 to get 1/16. -2, because its the same as 1/4^2 = 1/16
log(50/16) - log50 = log(50/16*50) (16*50 because both are in the denominator)
50/16*50 is the same as 1/16
Log base 4 of 1/16. What exponent would you use on 4 to get 1/16. -2, because its the same as 1/4^2 = 1/16
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log_4(50) - log_4(16) - log_4(50)
rearrange terms:
log_4(50) - log_4(50) - log_4(16)
first two terms add to 0 so you are left with
- log_4(16)
since log_4(16) = 2 ...[as 4²=16], you are left with
- 2
good luck
rearrange terms:
log_4(50) - log_4(50) - log_4(16)
first two terms add to 0 so you are left with
- log_4(16)
since log_4(16) = 2 ...[as 4²=16], you are left with
- 2
good luck