A spring with spring constant k is attached to a wall. OTher end is attached to some object of mass m
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A spring with spring constant k is attached to a wall. OTher end is attached to some object of mass m

[From: ] [author: ] [Date: 11-12-11] [Hit: ]
If you approach it using elastic energy stored = 1/2 kx^2,1/2(0+F)x = 1/2 kx^2 , assuming Hookes law applies.Hope it helps.Note: Not sure why you use F x(work) = 1/2kx^2. No such relation.......
IF the mass m is pushed to compress the spring with force F, what will be the maximum compression and the maximum velcoity attained by mass m. PLZ help

I tried this way : for max compression F = kx so x = F/k
but we can also do it like this : Fx(work) = 1/2kx^2(energy stored in spring) so x = sqrt(2F/k)
Im getting two answers and i have no idea how to find max velcoity
cmon guys plz help

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The answer should be x = F/k

If you approach it using elastic energy stored = 1/2 kx^2, then
Avg force x max compression = 1/2 kx^2
1/2(0+F)x = 1/2 kx^2 , assuming Hooke's law applies.
You arrive at the same answer x = F/k

Hope it helps.

Note: Not sure why you use F x(work) = 1/2kx^2. No such relation.
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