I have
y = (x^2 + 1)^(1/2) + e^C do i distribute ln
so,
ln(y) = ln(x^2 + 1)^(1/2) + ln(e^C)
this doesnt seem right to me
y = (x^2 + 1)^(1/2) + e^C do i distribute ln
so,
ln(y) = ln(x^2 + 1)^(1/2) + ln(e^C)
this doesnt seem right to me
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No, that's not right. We don't really have a way of dealing with logarithm of a sum.