What is the number of ions in 5.5x10^3 kg of Na2SO4
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What is the number of ions in 5.5x10^3 kg of Na2SO4

[From: ] [author: ] [Date: 11-12-06] [Hit: ]
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I really this for my chemistry homework tomorrow!

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Na has a charge of +2 and O has a charge of +1, so.......................... then that means that Na2 (+2) SO4 (-1) would have 8 ions

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5.5 x 10^3kg Na2SO4 x 1000g/1kg x 1molNa2SO4/ 142.04gNa2SO4 x 3 mols of ions Na2SO4/1molNa2SO4 x 6.02 x 10^23 ions/ 1 mol of ionNa2SO4. == 6.993 x 10^ 28 ions Na2SO4

Let me break this down. First you start with the given value. Then you convert into grams, as this is needed for the next step.

Next you convert using the double unit, grams/mol. there are 142.04g in one mole of Na2SO4.
Next, in one mole of Na2SO4, there are 3 mols of ions. (two ions for sodium and one polyatomic ion, sulfate).
Then for each mole of ion, there are 6.02 x 10^23 ions. So you multiply by this number. (avogadro's number)

Edit: if you only need mols of ions, then you can cut out the last step. Based on the wording, it seems like you need the actual number of ions though.

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Whats an ion? Sony judge me, im young. And God loves you very much even if you don't love him John 3:16
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