Ellipse 9x^2+25y^2=144, how do I solve this? It's confusing me...
Find the Foci, vertices, eccentricity, and length of the major and minor axis...
Find the Foci, vertices, eccentricity, and length of the major and minor axis...
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9x² + 25y² = 144
Divide both sides by 144
(9/144)x² + (25/144)y² =1
x²/(144/9) + y²/(144/25) = 1
x²/16 + y²/(12/5)²=1
x²/4² + y²/(12/5)² = 1
a= 4 and b= 12/5 = 2.4
f = √(a² -b²) = √(16 - 144/25) = 16/5 = 3.2
e= f/a = (16/5)/4 = 4/5
Divide both sides by 144
(9/144)x² + (25/144)y² =1
x²/(144/9) + y²/(144/25) = 1
x²/16 + y²/(12/5)²=1
x²/4² + y²/(12/5)² = 1
a= 4 and b= 12/5 = 2.4
f = √(a² -b²) = √(16 - 144/25) = 16/5 = 3.2
e= f/a = (16/5)/4 = 4/5
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x^2 / (1/3)^2 + y^2 / (1/5)^2 = 12^2 is the form you want.