Consider the system: x' - y' = 6y, x' + 2y' = 3x. where x(0) = 9; y(0) = -4. Then if Y(s) = L{y(t)}, Y(s) =
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HOME > > Consider the system: x' - y' = 6y, x' + 2y' = 3x. where x(0) = 9; y(0) = -4. Then if Y(s) = L{y(t)}, Y(s) =

Consider the system: x' - y' = 6y, x' + 2y' = 3x. where x(0) = 9; y(0) = -4. Then if Y(s) = L{y(t)}, Y(s) =

[From: ] [author: ] [Date: 11-12-03] [Hit: ]
Its not multiplication.And the L is a laplace transform.If youre confused by the question then dont answer.-It all depends on whats T because two variables side by side means you need to multiply. If you dont know what Y is then you can only go so far until you can no longer simplify the question. You also need to know whats L since its right next to the parenthesis.......
How would you go about solving this?

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@Greg y(t) is a function you toss pot. Its not multiplication. And the L is a laplace transform. If you're confused by the question then dont answer.

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It all depends on what's T because two variables side by side means you need to multiply. If you don't know what Y is then you can only go so far until you can no longer simplify the question. You also need to know what's L since it's right next to the parenthesis. You can't multiply a number times a letter or a letter times a letter it isn't possible
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keywords: 039,4.,system,Consider,Then,if,where,the,Consider the system: x' - y' = 6y, x' + 2y' = 3x. where x(0) = 9; y(0) = -4. Then if Y(s) = L{y(t)}, Y(s) =
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