A manufacturer pf sprinkler systems designed for fire protection claims that the average activating temperature is at laest 135 degree F. To test this claim, you randomly select a sample of 32 systems and find themean activation temperature to be 133 degree F, with a SD of 3.3 degree. At alfa=0.10, do you rejects null or fail to reject?
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The observed test statistic value is
t = (133 - 135)/(3.3/Sqrt32) = -3.428.
The two tailed critical values at 0.01 level for t-distribution for 31df are -2.75 and 2.75.
Observed t value -3.428 is smaller than -2.75 and so, reject Ho.
t = (133 - 135)/(3.3/Sqrt32) = -3.428.
The two tailed critical values at 0.01 level for t-distribution for 31df are -2.75 and 2.75.
Observed t value -3.428 is smaller than -2.75 and so, reject Ho.