What is the integral... ∫[(e^x + e^-x)/e^2x] dx

What is ∫[(e^x + e^-x)/e^2x] dx

i know that e^x reproduces itself, so i am kind of confused how to find this answer

Thank you for helping!

∫[(e^x + e^-x) / e^(2x)]dx
= ∫(e^(-x) + e^(-3x))dx
= ∫e^(-x)dx + ∫e^(-3x)dx
= -e^(-x) + (-1/3)e^(-3x) + C

Hope this helps :D

∫[(e^x + e^-x)/e^2x] dx
= ∫[(e^--x + e^--3x)] dx
= -- e^--x -- (1/3) e^--3x + C

use a calculator :D

= ∫(e^-x + e^-3x) dx = ...

idk