tan((4npi)/(4+16n))
I tried taking the limit as n approaches infinity but how in the world do I find the limit for that function?
I tried taking the limit as n approaches infinity but how in the world do I find the limit for that function?
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lim 4nπ/(4 + 16n) = π/4
n->∞
Moreover, 0 ≤ 4nπ/(4 + 16n) < π/4 for all n. So
lim tan(4πn/(4 + 16n) = tan(π/4) = 1.
n->∞
n->∞
Moreover, 0 ≤ 4nπ/(4 + 16n) < π/4 for all n. So
lim tan(4πn/(4 + 16n) = tan(π/4) = 1.
n->∞