Please help to find x

(4/x^2)+2x.......i need to find x. i already know that it is 3(square-root(-2)) but what i do not understand is HOW? please show me steps.

does the equation equal to zero? if it does then:

(4/x^2) + 2x = 0
4/x^2 = -2x

multiply the x^2 over then you have
4 = -2x^3
4/-2 = x^3
-2 = x^3
x = cuberoot(-2) ( not 3 square root -2) :]

hope this helps

i'm just going assume that (4/x²) + 2x = 0

1. times the whole equation by x²
x² ((4/x²) +2x) = x²(0)
4 + 2x³ = 0

2. get the x on one side
2x³ = -4

3. Divide by 2
x³ = -2

4. Cube root both sides
x = 3(square-root(-2)) or a neater way x = -2^1/3