Help with some algebra 1 homework
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Help with some algebra 1 homework

[From: ] [author: ] [Date: 11-11-08] [Hit: ]
666664. First, treat it as a normal equation and isolate y:2x-3y = 6-3y = 6 - 2xy = (6-2x)/(-3)y = 2/3*x - 2You then have your curve. Then do a test. Take a value under the curve (e.g.......
-1 = -3(6) + b
-1 = -18 + b
b = -1+18 = 17
Your equation is y = -3x + 17

2. Parallel to the x axis means no slope at all (or a 0 slope)
Since you want a line below the axis, any equation of the form y = -k would do. (Where k is a positive real number)

3. X varies directly means that it's a linear equation where b=0 (form y = mx)
You solve like in number 1:
22 = m*6
m = 22/6 = 3,66666

4. First, treat it as a normal equation and isolate y:
2x-3y = 6
-3y = 6 - 2x
y = (6-2x)/(-3)
y = 2/3*x - 2
You then have your curve.

Then do a test. Take a value under the curve (e.g. (0,-3)) and see if the condition is respected:
2(0)-3(-3)=9 > 6, so the solution is not downwards of the curve.
Hence, it is upwards.
edit: note that the curve for the inequality is dotted, and not full.

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1. For the line to be parallel it has to have the same slope, and you know the points it should go through. Therefore, you can write your equation as
-1=-3(6)+b
-1=-18+b
17=b
Final equation y=-3x+17
2. Same thing, same slope as the x axis which has a slope of 0. Therefore, its just y=0x+b where b can be anything.
3. I dont know what "x varies directly as y" means, sorry
4. How am I supposed to graph this? Sorry again
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