A ferris wheel had a diameter of 250 ft. its 36 passenger cabs could hold a total of 2160 people. if the cabs were evenly spaced how far apart would they be?
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You basically need to get the circumference of the Ferris wheel and divide that by 36.
250*3.14(pi) = 785
785/36 = 21.806 ft
If you want the shortest distance (straight line from cab to cab) instead of an arc length, that would be 21.7889 ft
http://www.wolframalpha.com/input/?i=36-gon+side+length+when+diameter+%3D+250
250*3.14(pi) = 785
785/36 = 21.806 ft
If you want the shortest distance (straight line from cab to cab) instead of an arc length, that would be 21.7889 ft
http://www.wolframalpha.com/input/?i=36-gon+side+length+when+diameter+%3D+250