Q: Differentiate f(x) = 1 + xe^x / x - e^x
Can someone explain how to solve this question?
Can someone explain how to solve this question?
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you will have to differentiate this by the form
d/dx(u/v)=(vdu/dx-udv/dx)/v^2
now for differentiating xe^x you will do it this way
xd/dx(e^x)+e^xd/dx(x)
giving you xe^x+e^x
I think you can do this now if not then you can find calculus help at the link given
http://math.tutorvista.com/calculus.html
d/dx(u/v)=(vdu/dx-udv/dx)/v^2
now for differentiating xe^x you will do it this way
xd/dx(e^x)+e^xd/dx(x)
giving you xe^x+e^x
I think you can do this now if not then you can find calculus help at the link given
http://math.tutorvista.com/calculus.html
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f(x) = 1 + xe^x / x - e^x
(x*e^x)/x = e^x
f(x) = 1 + e^x - e^x
f(x) = 1
isn't to hard then
I think you forgot some (()), if you change it a little i'll give it another look.
(x*e^x)/x = e^x
f(x) = 1 + e^x - e^x
f(x) = 1
isn't to hard then
I think you forgot some (()), if you change it a little i'll give it another look.