Sinα = 4/5 and Cosβ = 5/13
Sin2α
Cos2α
Sinαβ
Tan2α
Cos1/2β
Tan1/2α
Sin1/2α
Can You Please show me how to do this practice problems step by step!! :) i have a test on this tomorrow and can seem to understand these!! :/ I would really appreciate it :D
Sin2α
Cos2α
Sinαβ
Tan2α
Cos1/2β
Tan1/2α
Sin1/2α
Can You Please show me how to do this practice problems step by step!! :) i have a test on this tomorrow and can seem to understand these!! :/ I would really appreciate it :D
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sinA = 4/5, the other side has to be 3.
sin(2A)
= 2sinAcosA
= 2(4/5)(3/5)
= 24/25
cos(2A)
= cos^2(A) - sin^2(A)
= (3/5)^2 - (4/5)^2
= 9/25 - 16/25
= -7/25
tan(2A)
= sin(2A)/cos(2A)
= 24/-7
= -24/7
sin(2A)
= 2sinAcosA
= 2(4/5)(3/5)
= 24/25
cos(2A)
= cos^2(A) - sin^2(A)
= (3/5)^2 - (4/5)^2
= 9/25 - 16/25
= -7/25
tan(2A)
= sin(2A)/cos(2A)
= 24/-7
= -24/7