Given that
A=2i + 3j
and
B=3i - 4j
find the angle of
C=A+B
please write all the steps and formulas to calculate the above numerical clearly.thanks in advance
A=2i + 3j
and
B=3i - 4j
find the angle of
C=A+B
please write all the steps and formulas to calculate the above numerical clearly.thanks in advance
-
Adding the two vectors we have C = 5i - j
tan θ = -1/5 .
Hence θ = -11.3°, below the i axis.
======================================
tan θ = -1/5 .
Hence θ = -11.3°, below the i axis.
======================================
-
You can add the components in the i and j directions separately:
2i + 3i = 5i
3j + (-4j) = -j
So the final vector C = 5i - j
The angle can be found using tan (theta) = -1/5, so inverse tan (-1/5) = -9 degrees (that is, 9 degrees below the j axis)
2i + 3i = 5i
3j + (-4j) = -j
So the final vector C = 5i - j
The angle can be found using tan (theta) = -1/5, so inverse tan (-1/5) = -9 degrees (that is, 9 degrees below the j axis)
-
C= 5 i + 7 j
angle tan x = 5/7
find x
angle tan x = 5/7
find x