If the total value of the coins is 200 cents, find the number of 10 cents and 5 cents coins in the bag.
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10x+5y = 200 ----> (1)
x+y = 30 ----> (2)
5x+5y = 150 ----> (3) (2) * 5
5x = 50 (1) - (3)
x= 10
y = 20
so 10 coins of 10 cents n 20 coins of 5 cents
x+y = 30 ----> (2)
5x+5y = 150 ----> (3) (2) * 5
5x = 50 (1) - (3)
x= 10
y = 20
so 10 coins of 10 cents n 20 coins of 5 cents
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let the number of nickels = n and dimes = d
n+d=30
10d+5n=200
two equations, two unknowns... you should be able to handle it from here.
n+d=30
10d+5n=200
two equations, two unknowns... you should be able to handle it from here.
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20 of 5 cent coins and 10 of 10 cent coins