I'm posting this math problem for a friend. She is having trouble solving this. It says that a race car's velocity increases from 4 meters per second to 36 meters per second in 4 seconds. She found acceleration: 8 meters per second squared. She needs to find final position. She thinks it is either 18 meters, 80 meters, or 272 meters. Please help!
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The Physics formula for distance traveled over time, with initial velocity, V₀, acceleratiopn, "a", and initial distance from "the start", d₀ is:
d(t) = d₀ + V₀t + ½at²
In your case:
• V₀ = 4 m/s
• a = 8 m/s² (as you have calculated correctly)
• d₀ = 0 m (we can only assume this ... as there is no other info about it)
• t = 4 s
∴ d(4) = 0 + 4(4) + ½(8)(4²)
d(4) = 16 + 64 = 80
∴ distance traveled during the 4 s period of acceleration, from 4 m/s to 36 m/s, is 80 m
Hope this helps! Cheers! :)
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d(t) = d₀ + V₀t + ½at²
In your case:
• V₀ = 4 m/s
• a = 8 m/s² (as you have calculated correctly)
• d₀ = 0 m (we can only assume this ... as there is no other info about it)
• t = 4 s
∴ d(4) = 0 + 4(4) + ½(8)(4²)
d(4) = 16 + 64 = 80
∴ distance traveled during the 4 s period of acceleration, from 4 m/s to 36 m/s, is 80 m
Hope this helps! Cheers! :)
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