How many committees consisting of 3 female and 5 male students can be selected from a group of 5 female and 8 male students?
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This uses combinations.
Out of 5 females you will choose 3. Out of 8 males you will choose 5.
5C3 = 10 while 8C5 = 56. By the multiplication rule, there are 10 * 56 or 560 ways to do this.
Out of 5 females you will choose 3. Out of 8 males you will choose 5.
5C3 = 10 while 8C5 = 56. By the multiplication rule, there are 10 * 56 or 560 ways to do this.
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2