f(x)=8^(x)log(subscript 6)(x)
=> f'(x)=8^(x) * ln8 * log(subscript 6)(x) + 8^(x) * 1/(x*ln6)
=> f'(x)=8^(x) * [ 2log(subscript 6)(x) + 1/(x*ln6) ]
=> f'(x)=8^(x) * ln8 * log(subscript 6)(x) + 8^(x) * 1/(x*ln6)
=> f'(x)=8^(x) * [ 2log(subscript 6)(x) + 1/(x*ln6) ]
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TOTALLY know what you're talking about.