5) What is the density of an unknown metal that has a mass of 158 g and a volume of 20 ml?
Easy 10 points for best answer!
Easy 10 points for best answer!
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Density = mass / volume
Mass = 158 g
Divide by 1000 to change to kg.
158 ÷ 1000 = 0·158 kg
Volume = 20 ml = 20 cm³
Divide by 1000000 to change to m³.
20 ÷ 1000000 = 0·00002 m³
Density = 0·158 ÷ 0·00002 = 7900 kg/m³
I hope this helps.
Mass = 158 g
Divide by 1000 to change to kg.
158 ÷ 1000 = 0·158 kg
Volume = 20 ml = 20 cm³
Divide by 1000000 to change to m³.
20 ÷ 1000000 = 0·00002 m³
Density = 0·158 ÷ 0·00002 = 7900 kg/m³
I hope this helps.
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The density should be in units of kg/cubic meter.
20ml is 20x10^-6 m^3. So density is 0.158x10^6/20 kgm^-3.
20ml is 20x10^-6 m^3. So density is 0.158x10^6/20 kgm^-3.
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simply divide mass by volume.
density = 158 / 20
........... = 7.9 g/ml
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or
........... = 7.9 kg/l
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density = 158 / 20
........... = 7.9 g/ml
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or
........... = 7.9 kg/l
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First of all, remember that 20 ml = 20 cm^3
ρ = mass / volume
ρ = 158g / 20 cm^3
ρ = 7.9g/cm^3
ρ = mass / volume
ρ = 158g / 20 cm^3
ρ = 7.9g/cm^3
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The density is also unknown.
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Density is mass (Kg) divided by volume (L)
so 0.158/0.02
so 0.158/0.02