What is the density of an unknown metal (10 points)
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What is the density of an unknown metal (10 points)

[From: ] [author: ] [Date: 11-09-26] [Hit: ]
Divide by 1000000 to change to m³.I hope this helps.-The density should be in units of kg/cubic meter.20ml is 20x10^-6 m^3.So density is 0.158x10^6/20 kgm^-3.......
5) What is the density of an unknown metal that has a mass of 158 g and a volume of 20 ml?

Easy 10 points for best answer!

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Density = mass / volume

Mass = 158 g
Divide by 1000 to change to kg.
158 ÷ 1000 = 0·158 kg

Volume = 20 ml = 20 cm³
Divide by 1000000 to change to m³.
20 ÷ 1000000 = 0·00002 m³

Density = 0·158 ÷ 0·00002 = 7900 kg/m³

I hope this helps.

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The density should be in units of kg/cubic meter.

20ml is 20x10^-6 m^3. So density is 0.158x10^6/20 kgm^-3.

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simply divide mass by volume.

density = 158 / 20
........... = 7.9 g/ml
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or
........... = 7.9 kg/l
░░░░░░░░░░░░

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First of all, remember that 20 ml = 20 cm^3

ρ = mass / volume

ρ = 158g / 20 cm^3

ρ = 7.9g/cm^3

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The density is also unknown.

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Density is mass (Kg) divided by volume (L)

so 0.158/0.02
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