Hence, sec^2x = 2 ....? 10 points for best answer

Hi, I'm stuck on a question...
a) secx = square root of 2
I got 45 and 315 degree for that question..

part b) Hence find, sec^2x = 2
I'm stuck on that bit!! Thanks in advance!

a) secx = √2
=> 1/cosx = 1/√2
=> cosx = √2

=> x = ± π/4 which is 45 and 315 degree.

b) sec^2x = 2
=> 1/cos^2x = 1/2
=> cos^2x = 2
=> cosx = ± √2

x = π/4, 3π/4, 5π/4 or 7π/4 (if 0 ≤ x ≤ 2π)

tsk...if sec ² x = 2 then sec x = ± √2---> 45 + n 90