5, then each will have 12M & you can subtract one from the other to eliminate M.1.5*(8M + 12B) = 1.5*190012M + 18B = 2850Now subtract the second equation from the first12M + 16B = 2700-12M + 18B = 2850=12M - 12M + 16B - 18B = 2700 - 2850-2B = -150B = (-150)/(-2) = 75, so a boy makes rs.......
=
12M - 12M + 16B - 18B = 2700 - 2850
-2B = -150
B = (-150)/(-2) = 75, so a boy makes rs.75 per day
Plug that into any of the equations to find what a man makes
12M + 16B = 2700
12M + 16(75) = 2700
12M + 1200 = 2700
12M = 1500
M = 1500/12 = 125, a man makes rs.125 per day
How long will it take for 4 men & 4 boys to earn rs.8000?
We will say it is D number of days
D days * (4 * 125 + 4 * 75) = 8000
D * (500 + 300) = 8000
800D = 8000
D = 10 days
I'm guessing all men make one amount of money per hour & all boys make a second amount. M = amount men make per day, B = amount boys make per day
4 days * (3M + 4B) = 2700
so 12M + 16B = 2700
4 days * (2M + 3B) = 1900
so 8M + 12B = 1900
So now you have to solve the two simultaneous equations. Multiply the second one by 1.5, then each will have 12M & you can subtract one from the other to eliminate M.
1.5*(8M + 12B) = 1.5*1900
12M + 18B = 2850
Now subtract the second equation from the first
12M + 16B = 2700
-
12M + 18B = 2850
=
12M - 12M + 16B - 18B = 2700 - 2850
-2B = -150
B = (-150)/(-2) = 75, so a boy makes rs.75 per day
Plug that into any of the equations to find what a man makes
12M + 16B = 2700
12M + 16(75) = 2700
12M + 1200 = 2700
12M = 1500
M = 1500/12 = 125, a man makes rs.125 per day
How long will it take for 4 men & 4 boys to earn rs.8000?
We will say it is D number of days
D days * (4 * 125 + 4 * 75) = 8000
D * (500 + 300) = 8000
800D = 8000
D = 10 days