lx^2+x-1l=1 um.... I can't figure out how to solve this problem if someone could show me how to do it step by step I would be grateful.
Thanks
Thanks
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If | A | = C, then A=C or A= -C
so,
| X^2 + X - 1 | = 1 implies
X^2 + X - 1 = 1 or X^2 + X - 1 = -1
X^2 + X -2 = 0 or X^2 +X = 0
(X +2)(X-1) = 0 or X(X+1) = 0
X = -2 or X = 1 or X=0 or X = -1 would all satisfy the original equation.
so,
| X^2 + X - 1 | = 1 implies
X^2 + X - 1 = 1 or X^2 + X - 1 = -1
X^2 + X -2 = 0 or X^2 +X = 0
(X +2)(X-1) = 0 or X(X+1) = 0
X = -2 or X = 1 or X=0 or X = -1 would all satisfy the original equation.