As in what am i meant to do
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well, I am not sure what this means if you said it correctly. anything with dy/dx is talking about calculus. If you are taking a differential equations class, you probably need to make it look like:
dy/y=dx/x
and you must integrate both sides: lnIyI + C = lnIxI + C
Not sure what to tell you from there. sorry
dy/y=dx/x
and you must integrate both sides: lnIyI + C = lnIxI + C
Not sure what to tell you from there. sorry
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x(dy/dx) = y
Since you have a dy and a dx, you wil have to integrate it, but first you gotta manipulate the variables in the appropriate place.
x(dy/dx) = y
dy/dx = y/x
dy/y = dx/x
integrate both sides.
∫(1/y)dy = ∫(1/x)dx
ln|y| = ln|x| + C
ln|y| - ln|x| = C
ln|y/x| = C
Take e^ on both sides.
y/x = e^C
y = xe^C
Hope this helps :D
And if you were given an initial condition... you wanna plug your values in
at ln|y/x| = C, cuz thats when the C is the least affected.
Since you have a dy and a dx, you wil have to integrate it, but first you gotta manipulate the variables in the appropriate place.
x(dy/dx) = y
dy/dx = y/x
dy/y = dx/x
integrate both sides.
∫(1/y)dy = ∫(1/x)dx
ln|y| = ln|x| + C
ln|y| - ln|x| = C
ln|y/x| = C
Take e^ on both sides.
y/x = e^C
y = xe^C
Hope this helps :D
And if you were given an initial condition... you wanna plug your values in
at ln|y/x| = C, cuz thats when the C is the least affected.
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maybe differentiate the equation?