Write an equation in slope intercept form, for a line that satisfies the following condition: x-intercept 6, and y-intercept 20.
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y=mx+b
(0)=m(6)+b
-b=6m
-b/6=m
(20)=m(0)+b
20=b
m=-b/6
m=-20/6
m=-10/3
y=(-10/3)x+20
(0)=m(6)+b
-b=6m
-b/6=m
(20)=m(0)+b
20=b
m=-b/6
m=-20/6
m=-10/3
y=(-10/3)x+20
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Consider the eq. of a line:
y= mx+b
first, we know that b is the y intercept, so b=20.
plug in 0 for y, and 6 for x, because at the x intercept, y=0. Do this to solve for m.
m=-20/6
now, plug m and b into the first equation to obtain the final result:
y = -20/6x +20
And there you go.
y= mx+b
first, we know that b is the y intercept, so b=20.
plug in 0 for y, and 6 for x, because at the x intercept, y=0. Do this to solve for m.
m=-20/6
now, plug m and b into the first equation to obtain the final result:
y = -20/6x +20
And there you go.
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m = -20/3 the change in y divided by change in 6
y-20 = -20/3(x-0)
y = -20x/3 + 20
y-20 = -20/3(x-0)
y = -20x/3 + 20