∫[(2 - 3x )³/√x] dx
-
Probably the best thing to do is just expand.
∫(2-3x)^3* x^(-1/2) dx=
∫[2^3-3(2^2)(3x)+3(2)(3x)^2-(3x)^3]*x^(… dx
= ∫8x^(-1/2)-36x^(1/2)+ 54x^(3/2)- 27x^(5/2) dx
Then integrate term by term...
Hoping that helps!
∫(2-3x)^3* x^(-1/2) dx=
∫[2^3-3(2^2)(3x)+3(2)(3x)^2-(3x)^3]*x^(… dx
= ∫8x^(-1/2)-36x^(1/2)+ 54x^(3/2)- 27x^(5/2) dx
Then integrate term by term...
Hoping that helps!