A jet airliner moving initially at 290 mi/h due east enters a region where the wind is blowing at 100 mi/h in a direction 30.5° north of east. (Let the x-direction be eastward and the y-direction be northward.)
(a) Find the components of the velocity of the jet airliner relative to the air
(b) Find the components of the velocity of the air relative to Earth
(a) Find the components of the velocity of the jet airliner relative to the air
(b) Find the components of the velocity of the air relative to Earth
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a) Relative to the air flow, there are no components. The aircraft is doing 290mph. in the air, story ends. I think the question should be relative to the ground? For which you need (b) first.
b) Components of wind velocity and direction relative to ground = East, (cos 30.5) x 100 = 86.16mph., and north, (sin 30.5) x 100, = 50.75mph.
Should the question say for (a) relative to the ground, the east component of the aircraft's speed is then (100 + 86.16) = 186.16mph. Its north component is 50.75mph.
b) Components of wind velocity and direction relative to ground = East, (cos 30.5) x 100 = 86.16mph., and north, (sin 30.5) x 100, = 50.75mph.
Should the question say for (a) relative to the ground, the east component of the aircraft's speed is then (100 + 86.16) = 186.16mph. Its north component is 50.75mph.
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Get the sum of two vectors, J (airplane) velocity at 290 at 90* with x,y of 0,0 to 290,0 and A (air) velocity of 100 with x,y from 290,0 and off at an angle of 30.5* NofE or 30.5* from 0* (clockwise) or at an angle of 59.5* counterclockwise from the X axis (complement of 30.5*).
For the second part you can find the X and Y component of the 100 mph vector by trigonometry. Use the sine of 59.5* for the Y component, and the cosine of 59.5* for the X component.
From that you can answer the first part.
For the second part you can find the X and Y component of the 100 mph vector by trigonometry. Use the sine of 59.5* for the Y component, and the cosine of 59.5* for the X component.
From that you can answer the first part.