That's all my textbook asks and it gives 1.5 mg F-/L
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Molarity = concentration of a solute in a given volume of solution. Measured in moles per litre (mol L^-1) or Molar (M).
Molar mass of fluorine = 19g/mol
1.5 mg = 1.5 x 10^-3 g
#moles = mass/molar mass = 1.5*10^-3 / 19 = 7.89 x 10^-5
Since volume of solution was measured in litres, molarity = 7.89 x 10^-5 mol/L or 7.89 x 10^-5 M
Hope this helped :)
Molar mass of fluorine = 19g/mol
1.5 mg = 1.5 x 10^-3 g
#moles = mass/molar mass = 1.5*10^-3 / 19 = 7.89 x 10^-5
Since volume of solution was measured in litres, molarity = 7.89 x 10^-5 mol/L or 7.89 x 10^-5 M
Hope this helped :)