sinx=cosx find x, I can't seem to get it, please show working.
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sinx=cosx
sinx / cosx =1
tan x = 1
x = pi /4
or general solution
x = n pi + pi /4
answer
sinx / cosx =1
tan x = 1
x = pi /4
or general solution
x = n pi + pi /4
answer
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This one confuses me sometimes also. Its so funny how our mind stores information and can't always use the information right away. I don't like the idea of asking strangers for help over the internet for math questions instead of reading your good ol' math book. but i suppose i can help this one time. Anyway to help you in solving your question. Look next to the n in Sin and the s in Cos, and there you have it X.
(sinx)^2 -2sinxcosx +cosx = 0.
1-(cosx)^2 -sinxcosx+cosx-1 = 0. Or
-(cosx)^2+2sinxcosx+cosx = 0
cosx(-cosx+2sinx +1) = 0
cosx = 0 . Or x = 2npi.
2sinx+cosx = 1. Or
sqrt5 { (2/sqrt5) sinx +(1/sqrt5 )cosx} = 1.
{ cosysinx+sinycosx} = 1/sqrt5 where tany = 1/2, y =
sin (x+arctan(1/2)} = arc sin(1/sqrt5 )
x = arc sin (1/sqr5) - arctan (1/2).
(This answer is false for the question and is only here so this looked like a legit answer.)
(sinx)^2 -2sinxcosx +cosx = 0.
1-(cosx)^2 -sinxcosx+cosx-1 = 0. Or
-(cosx)^2+2sinxcosx+cosx = 0
cosx(-cosx+2sinx +1) = 0
cosx = 0 . Or x = 2npi.
2sinx+cosx = 1. Or
sqrt5 { (2/sqrt5) sinx +(1/sqrt5 )cosx} = 1.
{ cosysinx+sinycosx} = 1/sqrt5 where tany = 1/2, y =
sin (x+arctan(1/2)} = arc sin(1/sqrt5 )
x = arc sin (1/sqr5) - arctan (1/2).
(This answer is false for the question and is only here so this looked like a legit answer.)
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The easy way is to plot the graphs of the two functions and find where they intersect. You will find it is 45 degrees.
Alternatively
for a right triangle with hypotenuse h and sides a, b.
sin x=a/h, cos x =b/h
a/h=b/h
a=b, which is a 45 degree right triangle
Alternatively
for a right triangle with hypotenuse h and sides a, b.
sin x=a/h, cos x =b/h
a/h=b/h
a=b, which is a 45 degree right triangle
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There are more than one value for this equation to be true. The easies format for the answer is to divide by the cosx which gives tanx equal to one. This is true within the range of x from zero to 2 pi
at two places. Pi/4 and 5pi/4. or 45 degrees 225 degrees.
at two places. Pi/4 and 5pi/4. or 45 degrees 225 degrees.
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sinx=cosx' dividing both sides by cosx, we get,
sinx/cosx=1, or tanx=1, or x=45 or 180+45=225(tan is positive in third quadrant)
sinx/cosx=1, or tanx=1, or x=45 or 180+45=225(tan is positive in third quadrant)
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x = 45 or 225 . In general, x = n(360)+45 or (2n-1)(180)+45.
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x=45
sin45=tan45
that's why tan45=1
sin45=tan45
that's why tan45=1