Help i have a trigonometry question that i need help with thx
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Help i have a trigonometry question that i need help with thx

[From: ] [author: ] [Date: 11-08-23] [Hit: ]
Ahab will be 30cos40 = 22.98km North and 30sin40 = 19.Betty will be 60cos160 = -56.38km North or 56.38km South and 20.A) Ahab is 19.......
so the question is

Ahab and betty are at the pier.Ahab traels for 30km along 040T. Betty travels for 60km along 160T

A) how far east are Ahab and Betty from the pier?
B) How far north and south are betty and ahab fromthe pier?
C) calculate the bearing of betty from ahab at the final positions

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I assume 040T is a direction of 040° True and 160T is a direction of 160° True.

Ahab will be 30cos40 = 22.98km North and 30sin40 = 19.28km East of the pier
Betty will be 60cos160 = -56.38km North or 56.38km South and 20.52km East of the pier

A) Ahab is 19.28km East and Betty is 20.52km East of the pier
B) Ahab is 22.98km North and Betty is 56.38km South of the pier.
C) Betty is (22.98+56.38) = 79.36km South of Ahab and (20.52-19.28) = 1.24km East of Ahab. The bearing to Betty from Ahab is arctan(1.24/-79.36) = 179.1° True
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