If you found the answer to an equation in the form of a negative square root, (e.g. sqrt -4), what do you state (in an exam paper) to show that it is not a valid value?
Thanks!
Thanks!
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sqrt -4 could be shown as 4i
i being the imaginary number sqrt -1
or you could write "no real solutions"
i being the imaginary number sqrt -1
or you could write "no real solutions"
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if the given is in the negative form then automatically you will write " i " which means imaginary because An imaginary number is a number with square that is negative. When any real number is squared, the result is never negative. Imaginary numbers have the form bi where b is a non-zero real number and i is the imaginary unit, defined such that i 2 = −1
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The square root of a negative number is only invalid when you isolate your mathematics to the real number system. On a complex number system, your answer is equivalent to the following.
i = √(-1)
√(-4) * i = i√(4) = ±2i
i = √(-1)
√(-4) * i = i√(4) = ±2i
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At that point, you should have been trained on imaginary numbers based on the square root of -1, and how to use them. Look it up.
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negative square root will have a imaginary answer. like sq.root(-1)=i,
sq.root(-4)=sq.root(-1)sq.root(4)=2i.
good luck!!!
sq.root(-4)=sq.root(-1)sq.root(4)=2i.
good luck!!!
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Since you haven't yet learned about imaginary numbers,
then simply state that there is no real solution.
then simply state that there is no real solution.
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well the value does exist its just that it is imaginary
by the way the value is + or -2i
by the way the value is + or -2i
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√-4 = 2i
2i is an imaginary or complex number. It is not a real number solution.
2i is an imaginary or complex number. It is not a real number solution.
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imaginary value....i = sguare root of (-1); i*2= -1;
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Its imaginary.
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Here's what you say:
"No Real Solutions"
"No Real Solutions"