How to obtain the quadratic equation whose roots are the squares of the roots of the equation 2x^2 + 26x + 80=0?
thank you!
thank you!
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2x^2 + 26x +80 = 0
x^2 + 13x + 40 = 0
(x+5)(x+8) = 0
x = -5; -8
so you want a quadratic equation with roots 25 and 64
x = 25; x = 64
x -25 =0; x-64=0
(x-25)(x-64) = 0
x^2 - 89x + 1600 = 0
x^2 + 13x + 40 = 0
(x+5)(x+8) = 0
x = -5; -8
so you want a quadratic equation with roots 25 and 64
x = 25; x = 64
x -25 =0; x-64=0
(x-25)(x-64) = 0
x^2 - 89x + 1600 = 0
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