a) Line 1: y = [(-1/3)x]-2
Line 2: x+3y=6
b) Line 1: y= x+3
Line 2: y= -x+3
What are their solutions? Unique Solution ( Please give me the solution too) , no solution or infinitely many solution?
Line 2: x+3y=6
b) Line 1: y= x+3
Line 2: y= -x+3
What are their solutions? Unique Solution ( Please give me the solution too) , no solution or infinitely many solution?
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(a) Note that y = (-1/3)x - 2 and x + 3y = 6 have the same slope (you can solve x + 3y = 6 for y to get y = (-1/2)x + 3), but they are not the same line. This shows that the solution is inconsistent.
(b) By equating the y values, we see that:
x + 3 = -x + 3 ==> x = 0.
Then, by substituting x = 0 into either equation, y = 0 + 3 = 3. Thus, the solution to this system is (0, 3). Since there is one unique solution to do this system, it is consistent and independent.
I hope this helps!
(b) By equating the y values, we see that:
x + 3 = -x + 3 ==> x = 0.
Then, by substituting x = 0 into either equation, y = 0 + 3 = 3. Thus, the solution to this system is (0, 3). Since there is one unique solution to do this system, it is consistent and independent.
I hope this helps!
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It's my summer time, I don't feel like doing math, sorry. LOL. :) Use this website though; http://www.analyzemath.com/Calculators/C… . It's a calculator thing so it does the work for you, giving you the answer.