This is the equation I'm trying to solve: 5^x = 4+x. Any suggestions on how to solve this algebraically?
-
If you just want a single integer answer, you can get away with x = 1.
Otherwise:
http://www.wolframalpha.com/input/?i=5^x+%3D+4%2Bx
Otherwise:
http://www.wolframalpha.com/input/?i=5^x+%3D+4%2Bx
-
5x=4+x ..........5x-x=4........................…
if x is positive on the rigth if i go on the left it will be negative and vice vrsa
if x is multiplied on the rigth if i go on the left it will be divided and vice versa
if x is positive on the rigth if i go on the left it will be negative and vice vrsa
if x is multiplied on the rigth if i go on the left it will be divided and vice versa
-
4=5^x -x
x=1
lol. i checked and it works
prosess of elimination (guess and check)
me: hmmm it can't be more than 2...
idk how to show my work for this one sorry
x=1
lol. i checked and it works
prosess of elimination (guess and check)
me: hmmm it can't be more than 2...
idk how to show my work for this one sorry