Triangle ABC has area 1.
Points A' B' C' are selected on its sides BC CA and AB respectively.
Find area of triangle A'B'C'
given that AC':C'B = BA':A'C = CB':B'A = 1:2
Points A' B' C' are selected on its sides BC CA and AB respectively.
Find area of triangle A'B'C'
given that AC':C'B = BA':A'C = CB':B'A = 1:2
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1 -(4/9) is the area [1 - 2/3*2/3] = 5/9